Question
Using prime factorisation, find which of the following are perfect squares.$729$

Answer

Prime factors of $729 = (3 \times 3) \times (3 \times 3) \times (3 \times 3)$
As grouping, there is no unpaired factor left over.
$\begin{array}{c|c}3 & 729 \\ \hline3 & 243\\\hline3&81\\\hline3&27\\\hline3&9\\\hline3&3\\\hline3&1 \end{array}$
So, $729$ is a perfect square.

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