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Real Numbers — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsReal Numbers2 Marks
Question
Using prime factorization, find the HCF and LCM of:
$21, 28, 36, 45$
✓

Answer

$21 = 3 \times 7$
$28 = 2 \times 2 \times 7 = 2^2 \times 7$
$36 = 2 \times 2 \times 3 \times 3 = 2^2 \times 3^2$
$45 = 3 \times 3 \times 5 = 3^2 \times 5$
$HCF (21, 28, 36, 45) = 1$
$LCM (21, 28, 36, 45) = 2^2 \times 3^2 \times 5 \times 7 = 1260$

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