Question
Using prime factorization, find the $HCF$ and $LCM$ of:
$396, 1080$
$396, 1080$
✓
Answer
$396 = 2 \times 2 \times 3 \times 3 \times 11 = 2^2 \times 3^2\times 11$
$1080 = 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 5 = 2^3 \times 3^3 \times 5$
$HCF (396, 1080) = 2^2 \times 3^2 = 36$
$LCM (396, 1080) = 2^3 \times 3^3 \times 11 \times 5 = 11880$
$HCF \times LCM = 427680 144 \times 198 = 427680$
$\Rightarrow HCF \times LCM =$ product of given numbers Hence verified.
$1080 = 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 5 = 2^3 \times 3^3 \times 5$
$HCF (396, 1080) = 2^2 \times 3^2 = 36$
$LCM (396, 1080) = 2^3 \times 3^3 \times 11 \times 5 = 11880$
$HCF \times LCM = 427680 144 \times 198 = 427680$
$\Rightarrow HCF \times LCM =$ product of given numbers Hence verified.
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