Question
Using ruler and compasses only, construct a trapezium $\text{ABCD}$, in which the parallel sides $AB$ and $D$ Care $3.3 \ cm$ apart; $AB = 4.5\ cm, \angle A = 120^o BC = 3.6 \ cm$ and $\angle B$ is obtuse.
✓
Answer
Steps:
$1.$ Draw $A B=4.5 \ cm$.
$2.$ now draw $\angle BAS =120^{\circ}$ and draw $EA \perp AB$ such that $AX =3.3 \ cm$.
$3.$Through $X$ draws a line $QR$ which is parallel to $AB$ which cuts $AS$ at $D$.
$4.$ Through $B$ draw an arc taking radius $3.6 \ cm$ at $C$ on $PQ$.
$5.$ Join $CB.$
$\text{ABCD}$ is the required trapezium.
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