Question
Using ruler and compasses only, construct the quadrilateral $\text{ABCD}$, having given $AB = 5 \ cm, BC = 2.5 \ cm CD = 6 \ cm, \angle BAD = 90^o$ and diagonal $BD = 5.5 \ cm.$

Answer


Steps:
$1.$ Draw $A B=5 \ cm$.
$2.$ From A draw a line $A Y$ such that $\angle A=90^{\circ}$.
$3.$ Taking $B$ as a center with radius $5.5 \ cm$ draw an arc at $D$ on $A Y$.
$4.$ With $D$ and $B$ as center and radii, $6 \ cm$ and $2.5 \ cm$ draw arcs cutting each other at $C$.
$5.$ Join $DC$ and $BC$.
$\text{ABCD}$ is the required quadrilateral.

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