Using ruler and compasses only, construct the quadrilateral ABCD,… - Vidyadip

Question

Using ruler and compasses only, construct the quadrilateral $\text{ABCD}$, having given $A B=5 \ cm, B C=2.5 \ cm, C D$
$=6 \ cm$. $\angle B A D=90^{\circ}$ and the diagonal $A C=5.5 \ cm$.

✓

Answer

Steps:
$1$. draw $A B=5 \ cm$.
$2$. Now draw $\angle X A B$ such that it is $90^{\circ}$.
$3$. Taking $A$ and $B$ as a center and radius $2.5 \ cm$ and $5.5 \ cm$ draw arcs cut off at $C$.
$4$. Now join $B C$ and $A C$.
$5$. Taking $C$ as a center and radius $6 \ cm$ draw arcs at $D$ on $A X$.
$\text{ABCD}$ is the required quadrilateral.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "[4 marks sum]" from Construction of Polygons (Using ruler and compass only)→Construction of Polygons (Using ruler and compass only) — all question types→MATHEMATICS STD 9 question papers→ICSE Board STD 9 question papers→ICSE Board question paper generator→

Similar questions

If $a b c=1$, prove that : $\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$.

Solve the following systems of equations by using the method of cross multiplication:
5x - 4y + 2 = 0, 2x + 3y = 13

In the figure given below, $=LM = LN; \angle PLN 110^{\circ}$.

calculate: $(i) \angle LMN$
$(ii) \angle MLN$

If $p + q = 8$ and $p - q = 4$, find:$pq$

$\text{PQRS}$ is a parallelogram. $T$ is the mid$-$point of $PQ$ and $ST$ bisects $\angle PSR.$

Prove that: $QR = QT$

If $A=30^{\circ}$, verify that $\cos 2 \theta=\frac{1-\tan ^2 \theta}{1+\tan ^2 \theta}=\cos ^4 \theta-\sin ^4 \theta=2 \cos ^2 \theta-1-2 \sin ^2 \theta$

The monthly incomes of A and B are in the ratio 7 : 5 and their expenditures are in the ratio 3 : 2. If each saves ₹ 1500 per month, find their monthly incomes.

$AD$ is altitude of an isosceles triangle $\text{ABC}$ in which $AB = AC = 30 \ cm$ and $BC = 36 \ cm.$ A point $O$ is marked on $AD$ in such a way that $\angle BOC = 90^\circ.$ Find the area of quadrilateral $\text{ABOC}.$

Simplify:
$\left(\frac{a}{2 b}+\frac{2 b}{a}\right)^2-\left(\frac{2 b}{a}-\frac{a}{2 b}\right)^2$

A boy played $100$ games, gaining $Rs. 50$ on each game that he won, and losing $Rs. 20$ for each game that he lost. If on the whole he gained $Rs. 800,$ find the number of games that he won.