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Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsPolynomials2 Marks
Question
Using suitable identities Evaluate : $(102)^3$
✓

Answer

$(102)^3$
$=(100+2)^3=(100)^3+(2)^3+3(100)(2)(100+2)$
$\left(\text { Using Identity }(a+b)^3=a^3+b^3+3 a b(a+b)\right)$
$=1000000+8+600(100+2)=1000000+8+60000+1200$
$=1061208$

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