Gujarat BoardEnglish MediumSTD 9MathsPolynomials2 Marks
Question
Using suitable identity, evaluate the following:
$101 \times 102$
✓
Answer
$101 \times 102=(100+1)(100+2)$
Now using identity $(x+a)(x+b)=x^2+(a+b) x+a b$, we have
$(100+1)(100+2)=(100)^2+(1+2) 100+(1)(2)$
$=10000+(3) 100+2=10000+300+2$
$=10302$
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