ICSE BoardEnglish MediumSTD 6MATHSHCF and LCM3 Marks
Question
Using the common factor method, find the H.C.F. of 24, 36, 45 and 60
✓
Answer
$F_{24}=1,2,3,4,6,8,12,24$
$F_{36}=1,2,3,4,6,12,18,36$
$F_{45}=1,3,5,9,15,45$
$F_{60}=1,3,4,5,6,10,12,15,20,30,60$
Common factor between $24,36,45$ and $60=1,3$ H.C.F. of $24,36,45$ and $60=3$
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