MCQ
Using the digits 0, 2, 4, 6, 8 not more than once in any number, the number of 5 digited numbers that can be formed is:
  • A
    16
  • B
    24
  • C
    120
  • 96

Answer

Correct option: D.
96
Total number of 5 digit numbers will be 5!.
Among these the ones starting with 0, are 4!.
Hence the total number of 5 digit numbers will be
$5! - 4!$
$= 4!(4)$
$=24\times4$
$=96$

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