Question
Using the formula for squaring a binomial, evaluate the following:
$(1001)^2$

Answer

Here, we will use the identity $(a+b)^2=a^2+2 a b+b^2$.
$(1001)^2$
$=(1000+1)^2$
$=(1000)^2+2 \times 1000 \times 1+1^2$
$=1000000+2000+1$
$=1002001$

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