Question
Using the formula for squaring a binomial, evaluate the following:
$(99)^2$

Answer

Here, we will use the identity $(a+b)^2=a^2+2 a b+b^2$.
$(99)^2$
$=(100-1)^2$
$=(100)^2-2 \times 100 \times 1+1^2$
$=10000-200+1$
$=9801$

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