Question
Using the formula for squaring a binomial, evaluate the following:
$(999)^2$

Answer

Here, we will use the identity $(a+b)^2=a^2+2 a b+b^2$.
$(999)^2$
$=(1000-1)^2$
$=(1000)^2-2 \times 1000 \times 1+1^2$
$=1000000-2000+1$
$=998001$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free