Question
Using the relation E = hv, obtain the dimensions of Planck's constant.
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Answer
We know that dimensional formula of energy E of photon is [$M^1L^2T^{-2}$) and dimensional formula of frequency v is [$T^{-1}$] $[\text{h}]=\frac{[\text{E}]}{[\text{V}]}=\frac{\text{M}^{1}\text{L}^2\text{T}^{-2}}{[\text{T}^{-2}]}=[\text{M}^1\text{L}^2\text{T}^{-1}]$
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