Question
Using the relation E = hv, obtain the dimensions of Planck's constant.
✓
Answer
We know that dimensional formula of energy E of photon is [M1L2T-2) and dimensional formula of frequency v is [T-1]
$[\text{h}]=\frac{[\text{E}]}{[\text{V}]}=\frac{\text{M}^{1}\text{L}^2\text{T}^{-2}}{[\text{T}^{-2}]}=[\text{M}^1\text{L}^2\text{T}^{-1}]$
$[\text{h}]=\frac{[\text{E}]}{[\text{V}]}=\frac{\text{M}^{1}\text{L}^2\text{T}^{-2}}{[\text{T}^{-2}]}=[\text{M}^1\text{L}^2\text{T}^{-1}]$
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