Question
Using the standard electrode potentials given in Table $3.1,$ predict if the reaction between the following is feasible:
$Fe^{3+} (aq)$ and $Br^– (aq)$
$Fe^{3+} (aq)$ and $Br^– (aq)$
✓
Answer
$\text{Fe}^{3+}_\text{(aq)}+\text{e}^-\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ } \text{Fe}^{2+}_\text{(aq)}\Big]\times2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ;\ \ \ \ \ \ \ \ \ \ \ \ \text{E}^\circ=+0.77\ \text{V}\\2\text{Br}^-_\text{(aq)}\ \ \ \ \ \ \xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ } \text{Br}_{2\text{(I)}}+2\text{e}^-\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ;\ \ \ \ \ \ \ \ \ \ \ \text{E}^\circ=-1.09\ \text{V}\\\overline{2\text{Fe}^{3+}_\text{(aq)}+2\text{Br}^-_\text{(aq)}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ }2\text{Fe}^{2+}_\text{(aq)}\ \text{and}\ \text{Br}_{2\text{(I)}} \ \ \ \ \ ;\ \ \ \ \ \ \ \ \ \ \ \text{E}^\circ=-0.32\ \text{V}}$
Since $E^\circ$ for the overall reaction is negative, the reaction between $Fe^{3+} (aq)$ and $Br^− (aq)$ is not feasible.
Since $E^\circ$ for the overall reaction is negative, the reaction between $Fe^{3+} (aq)$ and $Br^− (aq)$ is not feasible.
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