Question
Using the standard electrode potentials given in the Table, predict if the reaction between the following is feasible:

Br2(aq) and Fe2+(aq).

Answer

The possible reaction between Br2(aq) and Fe2+(aq) is given by,

$\text{Br}_{2(\text{s})}+2\text{Fe}^{2+}_{(\text{aq})}\rightarrow2\text{Br}^-_{(\text{aq})}+2\text{Fe}^{3+}_{(\text{aq})}$

$\text{Oxidation half equation:}\ \ \ \ \ \ \ \text{Fe}^{2+}_{(\text{aq})}\xrightarrow{\ \ \ \ \ \ }\text{Fe}^{3+}_{(\text{aq})}+\text{e}^-]\times2\ \ ;\text{E}^\circ=-0.77\text{V}\\\text{Reduction half equation:}\ \ \text{Br}^{}_{2(\text{aq})}+2\text{e}^-\xrightarrow{\ \ \ \ \ }2\text{Br}^{-}_{(\text{aq})}\ \ \ \ \ \ \ \ \ ; \text{E}^\circ=+1.09\text{V}\\\overline{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}^{}_{2(\text{aq})}+2\text{Fe}^{2+}_{(\text{aq})}\xrightarrow{\ \ \ \ \ }2\text{Br}^{-}_{(\text{aq})}+2\text{Fe}^{3+}_{(\text{aq})}\ \ \ \ \ ;\text{E}^\circ=-0.32\text{V}$

Here, E° for the overall reaction is positive. Hence, the reaction between Br2(aq) and Fe2+(aq) is feasible.

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