Using the v - t graph, one can conclude: 1. Displacement in (0 - 4) seconds is equal to the displacement in (4 - 6) seconds. 2. Acceleration is 2.5-2ms in OA and zero in AB. 3. Acceleration is negative in time (6 - 8) seconds.

Using the v - t graph, one can conclude: 1. Displacement in (0 - …

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MCQ

Using the v - t graph, one can conclude:

Displacement in (0 - 4) seconds is equal to the displacement in (4 - 6) seconds.
Acceleration is 2.5^-2ms in OA and zero in AB.
Acceleration is negative in time (6 - 8) seconds.

A
Only A is correct.
B
Only B is correct.
C
Only C is correct.
D
All the three are correct.

✓

Answer

Only C is correct.

Explanation:

For the statement(A): Displacement in (0 - 4)s increasing and Displacement in (4 - 6)s is Constant. So, both the displacement of time (0 - 4)s and (4 - 6)s are not equal to each other.

For the statement(B):

Acceleration(OA) $=\frac{10}{4}=2.5\text{ms}$

Acceleration(AB) $=\frac{10}{(4+6)}=1\text{ms}$

For the statement(C): As we see that in the graph, part BC is decreasing simultaneously from 10m to 0. Hence, Statement C is the correct one.

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