Question
Value of $\sqrt[4]{(81)^{-2}}$ is:
✓
Answer
- $\frac{1}{9}$
Solution:
$\sqrt[4]{(81)^{-2}}$
$=\sqrt[4]{\frac{1}{(81)^2}}$
$=\sqrt[4]{\frac{1}{(9^2)^2}}$
$=\sqrt[4]{\frac{1}{9^4}}$
$=\Big(\frac{1}{9}\Big)^{4\times\frac{1}{4}}$
$=\frac{1}{9}$
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