Value of $\theta$ is increased gradually from $\theta = 0$ At $\theta=tan^{-1}(\frac{1}{2})$ both the block just start slipping. Then value of $\mu_2$ is : $(g = 10 m/s^2)$
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At limiting case $(10+20) g \sin \theta=[(10)(0.3)+$
$\left.20 \mu_{2}\right] g \cos \theta$
$\Rightarrow \mu_{2}=0.6$
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