Variation of electrostatic potential along x-direction is shown i… - Vidyadip

MCQ

Variation of electrostatic potential along $x$-direction is shown in the graph. The correct statement about electric field is

A
$x$ component at point $B$ is maximum
B
$x $ component at point $A$ is towards positive $x$-axis.
C
$x$ component at point $C$ is along negative $x-$ axis
✓
$x $ component at point $C$ is along positive $x$ -axis

✓

Answer

Correct option: D.

$x $ component at point $C$ is along positive $x$ -axis

d
Electric field $E_{x}=-\frac{d V}{d x} .$ So for negative slope, field will be directed along positive $x$. Thus $x$ component at point $A$ is towards negative $x$ $-axis$ and $x$ component at point $C$ is along positive $x$ $-axis$ and at point $B, x$ $-component$ of field will be minimum.

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