Question
Verify that $x =\frac{3}{4}, y =\frac{8}{9}$ and $z =-5$

Answer

$x =\frac{3}{4}, y =\frac{8}{9}$ and  $z =-5$
Using, $x \times( y - z )= x \times y - x \times z$
$\frac{3}{4} \times\left(\frac{8}{9}-(-5)\right)=\frac{3}{4} \times \frac{8}{9}-\frac{3}{4} \times(-5)$
$ \Rightarrow \frac{3}{4} \times\left(\frac{8 \times 1}{9 \times 1}+\frac{5 \times 9}{1 \times 9}\right)=\frac{2}{3}+\frac{15}{4}$
$ \Rightarrow \frac{3}{4} \times\left(\frac{8+45}{9}\right)=\frac{2 \times 4}{3 \times 4}+\frac{15 \times 3}{4 \times 3}$
$ \Rightarrow \frac{3}{4} \times \frac{53}{9}=\frac{8+45}{12}$
$ \Rightarrow \frac{53}{12}=\frac{53}{12}$

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