Question
Verify the following: $(5x + 8)^2- 160x = (5x - 8)^2$
✓
Answer
$(5x + 8)^2- 160x = (5x - 8)^2$
Taking $LHS$
$ =(5 x+8)^2-160 x $
$ =(5 x)^2+(8)^2+2 \times 5 x \times 8-160 x $
$ =(5 x)^2+(8)^2+80 x-160 x $
$ =(5 x)^2+(8)^2-80 x $
$ =(5 x)^2+(8)^2-2 \times 5 x-8 $
$ =(5 x-8)^2 $
$= RHS$
Hence verified
Taking $LHS$
$ =(5 x+8)^2-160 x $
$ =(5 x)^2+(8)^2+2 \times 5 x \times 8-160 x $
$ =(5 x)^2+(8)^2+80 x-160 x $
$ =(5 x)^2+(8)^2-80 x $
$ =(5 x)^2+(8)^2-2 \times 5 x-8 $
$ =(5 x-8)^2 $
$= RHS$
Hence verified
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