Question
Verify the following:
$\left(a^2-b^2\right)\left(a^2+b^2\right)+\left(b^2-c^2\right)\left(b^2+c^2\right)+\left(c^2-a^2\right)+\left(c^2+a^2\right)=0$

Answer

$\left(a^2-b^2\right)\left(a^2+b^2\right)+\left(b^2-c^2\right)\left(b^2+c^2\right)+\left(c^2-a^2\right)+\left(c^2+a^2\right)=0$
Taking $LHS$
$ =\left(a^2-b^2\right)\left(a^2+b^2\right)+\left(b^2-c^2\right)\left(b^2+c^2\right)+\left(c^2-a^2\right)+\left(c^2+a^2\right) $
$=\left(a^4-b^4+b^4-c^4+c^4-a^4\right)=0$
$= RHS$
Hence verified

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