Question
Verify the following: $(ab + bc)(ab - bc) + (bc + ca)(bc - ca) + (ca + ab)(ca - ab) = 0$

Answer

$(ab + bc)(ab - bc) + (bc + ca)(bc - ca) + (ca + ab)(ca - ab) = 0$
Taking $LHS$
$(ab + bc)(ab - bc) + (bc + ca)(bc - ca) + (ca + ab)(ca - ab)$
$ =\left[(a b)^2-(b c)^2\right]+\left[(b c)^2-(c a)^2\right]+\left[(c a)^2-(a b)^2\right] $
$=a^2 b^2-b^2 c^2+b^2 c^2-c^2 a^2+c^2 a^2-a^2 b^2=0 $
$= RHS$
Hence verified

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