Question
Very-Short and Short-Answer Qustions:
Write the value of $\frac{\tan^2\theta-\sec^2\theta}{\cot^2\theta-\text{cosec}^2\theta}.$

Answer

$\frac{\tan^2\theta-\sec^2\theta}{\cot^2\theta-\text{cosec}^2\theta}$
$=\frac{-1}{-1}$ $\big(1+\tan^2\theta=\sec^2\theta$ and $1+\cot^2\theta=\text{cosec}^2\theta\big)$
$=1$

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