MCQ
વિધેય $f(x)\, = \left\{ {\begin{array}{*{20}{c}}{1 + x,}&{x \le 2}\\{5 - x,}&{x > 2}\end{array}} \right.\,$ એ . .
- A$x = 2$ આગળ સતત નથી
- B$x = 2$ આગળ વિકલનીય નથી.
- ✓$x = 2$ સતત છે પરંતુ વિકલનીય નથી
- Dએકપણ નહી.
$\mathop {\lim }\limits_{h \to {0^ + }} 5 - (2 + h) = 3$, $f(2) = 3$
Hence, $f$ is continuous at $x = 2$
Now $Rf'(x) = \mathop {\lim }\limits_{h \to 0} \frac{{5 - (2 + h) - 3}}{h} = - 1$
$Lf'(x) = \mathop {\lim }\limits_{h \to 0} \frac{{1 + (2 - h) - 3}}{{ - h}} = 1$
$\because Rf'(x) \ne Lf'(x)$; $f$ is not differentiable at $x = 2$.
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