MCQ
વિકલ સમીકરણ $\frac{{dy}}{{dx}} = 1 + x + y + xy$ નો ઉકેલ મેળવો.
- ✓$\log (1 + y) = x + \frac{{{x^2}}}{2} + c$
- B${(1 + y)^2} = x + \frac{{{x^2}}}{2} + c$
- C$\log (1 + y) = \log (1 + x) + c$
- Dએકપણ નહી.
==> $\frac{{dy}}{{dx}} = (1 + x)(1 + y)$ ==> $\frac{{dy}}{{1+ y}} = (1 + x)dx$
On integrating, we get $\log (1 + y) = \frac{{{x^2}}}{2} + x + c$.
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