MCQ
વિકલ સમીકરણ $(x - {y^2}x)dx = (y - {x^2}y)dy$ નો ઉકેલ મેળવો.
- ✓$(1 - {y^2}) = {c^2}(1 - {x^2})$
- B$(1 + {y^2}) = {c^2}(1 - {x^2})$
- C$(1 + {y^2}) = {c^2}(1 + {x^2})$
- Dએકપણ નહી.
On integrating we get $ - \frac{1}{2}\log (1 - {x^2}) = - \frac{1}{2}\log (1 - {y^2}) + \log c$
==> $\log (1 - {x^2}) - \log (1 - {y^2}) = - 2\log c$ ==> $\frac{{1 - {x^2}}}{{1 - {y^2}}} = {c^{ - 2}}$
Hence $(1 - {y^2}) = {c^2}(1 - {x^2})$.
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