MCQ
Volume of a sphere whose radius is $7\ cm.$
- A$1430\text{cm}^3$
- ✓$1437\frac{1}{3}\text{cm}^3$
- C$1337\frac{1}{3}\text{cm}^3$
- D$1447\text{cm}^3$
✓
Answer
Correct option: B.
$1437\frac{1}{3}\text{cm}^3$
Volume of sphere $=\frac{4}{3}\pi\text{r}^3(\text{Given r}=7\text{cm})$
$=\frac{4}{3}\times\frac{22}{7}\times7^3$
$=\frac{88\times343}{7\times3}$
$=1437\frac{1}{3}\text{cm}^3$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write the correct answer in the following: Three angles of a quadrilateral are $75^\circ , 90^\circ$ and $75^\circ$. The fourth angle is:
→In a rhombus $ABCD,$ if $\angle\text{ACB} = 40^\circ,$ then $\angle\text{ADB} =\ ?$
→Write the correct answer in the following:
Degree of the zero polynomial is.
Degree of the zero polynomial is.
If the ratio of volumes of two spheres is 1/8 then the ratio of their surface areas is
If $x+a$ is a factor of $x^4-a^2 x^2+3 x-6 a$, then $a=$
→If $2^{5 x} \div 2^x=\sqrt[5]{2^{20}}$, then $x=$
→Find out the mode of the following: $5, 4, 3, 5, 6, 6, 6, 5, 4, 5, 5, 3, 2, 1$.
→If $\text{p}(\text{x})=\text{x}^2-2\sqrt{2}\text{x}+1,$ than $\text{p}(2\sqrt{2})$ is equal to:
→In the adjoining figure, $PQ = PR$. If $\angle\text{Q} = 70^\circ,$ then measure of $\angle\text{P}$ is:
→Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is: