Question
Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is:
$2H_2O(I) \rightarrow 2H_2 (g) + O_2(g)$
If a given experiment results in $2500\ cm^3$​​​​​​​ of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?

Answer

Given equation is: $2H_2O (I) \rightarrow 2H_2 (g) + O_2 (g)$
According to Gay$-$Lussac's law;
$2$ volume of water produces $2$ volume of hydrogen and $1$ volume of oxygen
i.e $2$ volume of water produces $= 2$ volume of hydrogen
$= 2500\ cm^3$​​​​​​​
$2$ volume of water will produce $=1$ volume of Oxygen
$= 2500/ 2 = 1250 \ cm^3$​​​​​​​
i.e $0= 1250 \ cm^3$​​​​​​​

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