Question
Water flows from a tank with a rectangular base measuring $80\ cm$ by $70\ cm$ into another tank with a square base of side $60\ cm$. If the water in the first tank is $45\ cm$ deep, how deep will it be in the second tank?
✓
Answer
Dimensions of rectangular base tank are $80\ cm \times 70\ cm.$
Height of rectangle base tank $= 45\ cm$
Each side of square base tank $= 60\ cm$
Let h be the height of square base tank
Volume of rectangular tank = Volume of square tank
$\Rightarrow80\times70\times45=60\times60\times\text{h}$ [$\because$ volume of cuboidal $= l \times b \times h]$
$\Rightarrow\frac{80\times70\times45}{60\times60}=\text{h}$
$\therefore\text{h}=70\text{cm}$
Hence, water in second tank will be $70\ cm$ deep.
Height of rectangle base tank $= 45\ cm$
Each side of square base tank $= 60\ cm$
Let h be the height of square base tank
Volume of rectangular tank = Volume of square tank
$\Rightarrow80\times70\times45=60\times60\times\text{h}$ [$\because$ volume of cuboidal $= l \times b \times h]$
$\Rightarrow\frac{80\times70\times45}{60\times60}=\text{h}$
$\therefore\text{h}=70\text{cm}$
Hence, water in second tank will be $70\ cm$ deep.
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