Wavelength of light used in an optical instrument are _1=4000 A a… - Vidyadip

MCQ

Wavelength of light used in an optical instrument are $\lambda_1=4000 \mathring A$ and $\lambda_2=5000 \mathring A$, then ratio of their respective resolving power (corresponding to $\lambda_1$ and $\lambda_2$ ) is

A
$16: 25$
B
$9: 1$
C
$4: 5$
✓
$5: 4$

✓

Answer

Correct option: D.

$5: 4$

R.P. $\propto \frac{1}{\lambda} $
$\Rightarrow \frac{(\text { R.P. })_1}{(\text { R.P. })_2}=\frac{\lambda_2}{\lambda_1}=\frac{5}{4}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Ray Optics→Ray Optics — all question types→JEE physics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

If velocity of a body is twice of previous velocity, then kinetic energy will become

The dipole moment of a circular loop carrying a current $I$, is $m$ and the magnetic field at the centre of the loop is $B_1$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_2$ . The ratio $\frac{{{B_1}}}{{{B_2}}}$ is

A wire of length $L$ metre carrying a current of $I$ ampere is bent in the form of circle. Its magnetic moment is

A transverse sinusoidal wave of amplitude $a$, wavelength $\lambda$ and frequency $n$ is travelling on a stretched string. The maximum speed of any point on the string is $v / 10$, where $v$ is the speed of propagation of the wave. If $a=10^{-3} \mathrm{~m}$ and $v=10 \mathrm{~ms}^{-1}$, then $\lambda$ and $n$ are given by

A short bar magnet with its north pole facing north forms a neutral point at $P$ in the horizontal plane. If the magnet is rotated by 90 in the horizontal plane, the net magnetic induction at $P$ is (Horizontal component of earth's magnetic field $=B_H$ )

Resistance of a voltameter is $2 \Omega$, it is connected in series to a battery of $10\ V$ through a resistance of $3 \Omega$. In a certain time mass deposited on cathode is $1 gm$. Now the voltameter and the $3 \Omega$ resistance are connected in parallel with the battery. Increase in the deposited mass on cathode in the same time will be

Stars are not visible in the day time because

When the wavelength of light coming from a distant star is measured it is found shifted towards red. Then the conclusion is

A cell of emf $90\,V$ is connected across series combination of two resistors each of $100\,\Omega$ resistance. A voltmeter of resistance $400\,\Omega$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be $.........\,V$

Inductance $L$ can be dimensionally represented as