MCQ
$\wedge^{{\circ}}_{\text{m}(\text{NH}_4\text{OH})}$ is equal to $.......$
- A$\wedge^{{\circ}}_{\text{m}(\text{NH}_4\text{OH})}+\wedge^{{\circ}}_{\text{m}(\text{NH}_4\text{Cl})}-\wedge^{{\circ}}_{\text{HCl}}$
- ✓$\wedge^{{\circ}}_{\text{m}(\text{NH}_4\text{Cl})}+\wedge^{{\circ}}_{\text{m}(\text{Na}\text{OH})}-\wedge^{{\circ}}_{(\text{Nacl})}$
- C$\wedge^{{\circ}}_{\text{m}(\text{NH}_4\text{Cl)}}+\wedge^{{\circ}}_{\text{m}(\text{Nacl})}-\wedge^{{\circ}}_{\text{NaOH}}$
- D$\wedge^{{\circ}}_{\text{m}(\text{NaOH})}+\wedge^{{\circ}}_{\text{m}(\text{NaCl})}-\wedge^{{\circ}}_{(\text{NH}_4\text{Cl})}$
