Question
What are four quantum numbers of $19^{th}$ electron of copper?

Answer

Cu(29): $1 s^2 ~2 s^2 ~2 p^6 ~3 s^2 ~3 p^6 ~4 s^1 ~3 d^{10}$
n = 4, l = 0, m = 0, s $=\frac{+1}{2}$

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