Question
What are the atomic numbers of elements whose outermost electrons are represented by
  1. 3s1
  2. 2p3
  3. 3p5?

Answer

  1. 3s1

Completing the electron configuration of the element as

1s2 2s2 2p6 3s1.

$\therefore$ Number of electrons present in the atom of the element

= 2 + 2 + 6 + 1 = 11

$\therefore$ Atomic number of the element = 11

  1. 2p3

Completing the electron configuration of the element as

1s2 2s2 2p3.

$\therefore$ Number of electrons present in the atom of the element = 2 + 2 + 3 = 7

$\therefore$ Atomic number of the element = 7

  1. 3p5

Completing the electron configuration of the element as

1s2 2s2 2p6 3s2 3p5 1s2 2s2 2p6 3s2 3p5

$\therefore$ Number of electrons present in the atom of the element = 2 + 2 + 6+2+5 = 17

$\therefore$ Atomic number of the element = 17

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