Question
What happens when dilute sulphuric acid is treated with $(a) \ Fe \ \ \ (b) \ CaF_2$?
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Answer
Dilute $H_2SO_4$ reacts with $Fe$ which is below hydrogen in the electrochemical series, with the evolution of $H_2$
When $H_2SO_4$ is added to calcium fluoride, hydrogen fluoride is obtained.
When $H_2SO_4$ is added to calcium fluoride, hydrogen fluoride is obtained.
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