Question
What happens when:
n-butyl chloride is treated with alcoholic KOH.

Answer


$\text{CH}_3\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{Cl}+\text{KOH(alc)}\xrightarrow[\text{Dehydrohalogenation}]{\Delta}\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2+\text{KCl}+\text{H}_2\text{O}\\ \ \text{n-Butychloride}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{But-1-ene}$

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