Question
What is expected Van't Hoff factor for $K _4\left[ Fe ( CN )_6\right]$ ?

Answer

$
K_4\left[Fe(CN)_6\right] \Leftrightarrow 4 K^{+}+\left[Fe(CN)_6\right]^{4-}
$
$\therefore$ Van't Hoff factor (i) $=5$, as 5 ions are formed on dissociation

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