What is integrating factor of dy dx +y = ? - Vidyadip

MCQ

What is integrating factor of $\frac{\text{dy}}{\text{dx}}+\text{y}\sec\text{x}=\tan\text{x}?$

✓
$\sec\text{x}+\tan\text{x}$
B
$\log(\sec\text{x}+\tan\text{x})$
C
$\text{e}^{\sec\text{x}}$
D
$\sec{\text{x}}$

✓

Answer

Correct option: A.

$\sec\text{x}+\tan\text{x}$

We have,
$\frac{\text{dy}}{\text{dx}}+\text{y}\sec\text{x}=\tan\text{x}$
Comparing with We get,
$\text{P}=\sec{\text{x}}, \text{Q}=\tan{\text{x}}$
Now,
$\text{I.F}=\text{e}^{\int\sec\text{x}\text{dx}}$
$=\text{e}^{\log(\sec\text{x}+\tan\text{x})}$
$=\sec\text{x}+\tan\text{x}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Differential Equations→Differential Equations — all question types→Maths STD 12 Science question papers→Maharashtra Board STD 12 Science question papers→Maharashtra Board question paper generator→

Similar questions

If in a triangle the angles are in A. P. and $b: c=\sqrt{3}: \sqrt{2}$, then $\angle A$ is equal to

Let $X \sim B(n, p)$, if $E(X)=5, \operatorname{Var}(X)=2.5$ then $P(X<1)=$

Let $\text{f}(\text{x})=\text{x}^3+\text{a}\text{x}^2+\text{b}\text{x}+5\sin^2\text{x}$ be an increasing function on R. Then, a and b satisfy:

If $\text{A}=\begin{bmatrix}2&-1&3\\-4&5&1\end{bmatrix}$ and $\text{B}=\begin{bmatrix}2&3\\4&-2\\1&5\end{bmatrix},$ then:

Let $\text{A}=\{\text{x}\in\text{R}:-1\leq\text{x}\leq1\}=\text{B}$ and $\text{C}=\{\text{x}\in\text{R}:\text{x}\geq0\}$ and let $\text{S}=\{(\text{x, y})\in\text{A}\times\text{B}:\text{x}^2+\text{y}^2=1\}$ and $\text{S}_0=\{(\text{x, y})\in\text{A}\times\text{C}:\text{x}^2+\text{y}^2=1\}.$ Then,

If $f(x)=\left\{\begin{array}{ll}4 x+3, & 1 \leq x \leq 2 \\ 3 x+5, & 2 < x \leq 4\end{array}\right.$, then $\int_1^4 f (x) d x=$

If the distance of the point $(1,1,1)$ from the origin is half its distance from the plane $x+y+ z + k =0$, then $k =$

The area of the region bounded by the curve $y=\cos x, X$-axis and the lines $x=0, x=2 \pi$ is

A random variable X has the following probability distribution:

X	1	2	3	4
P(X)	$\frac{1}{7}$	$\frac{2}{7}$	$\frac{3}{7}$	$\frac{1}{7}$

Then, the variance of this distribution is

If $A=\left[\begin{array}{lll}1 & 2 & 3 \\ 1 & 3 & 4 \\ 3 & 4 & 3\end{array}\right]$, then $A^{-1}=$