Alcohols, Phenols, and Ethers — Chemistry STD 12 Science — Question

In the first step, alkene reacts with diborane (B₂H₆) as boron hydride (BH₃) to form an alkyl borane. In the next step, the alkyl borane is oxidised by alkaline H₂O₂ to form an alcohol. The indirect hydration proceeds according to Anti Markovnikoff’s rule. For example,

$\text{3CH}_3\text{CH}=\text{CH}_2+\text{BH}_3\ \ \xrightarrow{\ \ \ \ }\ \ (\text{CH}_3\text{CH}_2\text{CH}_2)_3\text{B}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Tri-n-Propyl borate}\\ \ \ \ \ \ \ \ \ \ \ \ \\ \ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \xrightarrow[\text{H}_2\text{O}]{\text{H}_2\text{O}_2/\text{OH}^-}\text{3CH}_3\text{CH}_2\text{CH}_2\text{OH}+\text{H}_3\text{BO}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Propan-1-ol}\ \ \ \ \ \ \ \ \ \ \ \text{Boric acid}$