MCQ
What is the atomic number of the element with $M^{2+}$ ion having electronic configuration $\ce{[Ar]3d^8}?$
  • A
    $25$
  • $28$
  • C
    $27$
  • D
    $26$

Answer

Correct option: B.
$28$
$E.C$ of $M :\ \ce{[Ar]4s^23d^8}$
$E.C$ of $M^{2+}:\ \ce{[Ar]4s^03d^8}$
Total electrons $= 28 =$ atomic number.

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