MCQ
What is the bond angle in ammonia molecule?
- A106.5°
- B107°
- C108°
- D109.5°
Explanation:
The bond angle for a standard tetrahedral geometry is 109.5°. But the ammonia molecule contains a lone electron pair on nitrogen.
As it is closer to the N atom than the other orbitals, it creates a repulsive effect and pushes the Hydrogen atoms close to each other, thus reducing the bond angle to 107°.
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$\mathrm{x}=$ . . . . . . . . . (Nearest integer)
Given : $\left(\mathrm{K}_{\mathrm{r}}\right)_{\text {water }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$.
density of acetic acid is $1.2 \mathrm{~g} \mathrm{~mol}^{-1}$
molar mass of water $=18 \mathrm{~g} \mathrm{~mol}^{-1}$.
molar mass of acetic acid $=60 \mathrm{~g} \mathrm{~mol}^{-1}$.
density of water $=1 \mathrm{~g} \mathrm{~cm}^{-3}$
Acetic acid dissociates as
$\mathrm{CH}_3 \mathrm{COOH} \rightleftharpoons \mathrm{CH}_3 \mathrm{COO}^{\oplus}+\mathrm{H}^{\oplus}$