Question
What is the difference between displacement and double displacement reactions? Write equations for these reactions.

Answer

In displacement reaction, more reactive element displaces less reactive element from its solution. For example, In case of Zn and $Ag , Zn$ being more reactive than Ag , it displaces Ag from its solution of $AgNO _3$.
(i) $Zn ( s )+2 AgNO _3(aq)$ $\longrightarrow$$Zn\left(NO_3\right)_2(aq)+2 Ag(s)$
Similarly, Fe being more reactive displaces Cu from $CuSO _4$ solution.
(ii) $Fe ( s )+ CuSO _4( aq ) \longrightarrow$$FeSO_4(aq)+Cu(s)$
In double displacement reaction, two compounds exchange their ions to form two new compounds.
For example,
$\begin{array}{l} \text { (i) } Na _2 SO _4( aq )+ BaCl _2( aq )\longrightarrow BaSO _4(s)+2 NaCl ( aq )\end{array}$
${(ii)}2 KBr ( aq )+ BaI _2( aq ) \longrightarrow$ $2 KI (aq)+ BaBr _2(s)$

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