Question
What is the difference between Magnification and Magnifying power ?

Answer

MagnificationMagnifying power
(i) It is a liner magnificant which is equal to $\frac{h_2}{h_1}$.It is an angular magnification which is equals to $\frac{\angle \beta}{\angle \alpha}$.
(ii) Its value increases with the increase in V.Its value decreases with the increase in V.
(iii) Its value may be between $-\infty$ to $+\infty$.Its value may be between $\frac{ D }{f}$ and $l+\frac{ D }{f}$.
(iv) Under certain condition it is equal to magnifying power.It is a special condition of magnification when ve = D.

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The density of nuclear matter is the ratio of the mass of a nucleus to its volume. As the volume of a nucleus is directly proportional to its mass number A, so the density of nuclear matter is independent of the size of the nucleus. Thus, the nuclear matter behaves like a liquid of constant density. Different nuclei are like drops of this liquid, of different sizes but of same density. Let A be the mass number and R be the radius of a nucleus. If m is the average mass of a nucleon, then.

Mass of nucleus = mA

$\text{Volume of nucleus }=\frac{4}{3}\pi\text{R}^3=\frac{4}{3}\pi\big(\text{R}_0\text{A}\frac{1}{3}\big)=\frac{4}{3}\pi\text{R}^3_0\text{A}$

$\therefore\text{Nuclear density},\rho\text{nu}=\frac{\text{Mass of nucleus}}{\text{Volume of nucleus}}\text{or}\ \rho\text{nu}$

$=\frac{\text{MA}}{\frac{4}{3}\pi\text{R}_0^3\text{A}}=\frac{3\text{m}}{4\pi\text{R}_0^3}$

Clearly, nuclear density is independent of mass number A or the size of the nucleus. The nuclear mass density is of the order 1017kg m-3 This density is very large as compared to the density of ordinary matter, say water, for which $\rho$ = 1.0 × 103kg m-3

  1. The nuclear radius of $_8^{16}\text{O}$ is 3 × 10-15m. The density of nuclear matter is.
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  2. 1.2 × 1017kg m-3
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  1. What is the density of hydrogen nucleus in SI units? Given Ro= 1.1 fermi and mP = 1.007825 amu.
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  1. Density of a nucleus is.
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  2. More for heavier elements and less for lighter elements.
  3. Very less compared to ordinary matter.
  4. A constant.
  1. The nuclear mass of $_{23}^{56}\text{Fe}$ is 55.85 amu. The its nuclear density is.
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  1. If the nucleus of $_{13}^{27}\text{Al}$ has s a nuclear radius of about 3.6 fm, then $_{52}^{125}\text{Te}$ would have its radius approximately as.
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  2. 12fm
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