MCQ
What is the distribution of electrons in an oxygen atom:
- A$(2, 4)$
- B$(2, 8)$
- ✓$(2, 6)$
- D$(2, 10)$
The total number of electrons present in oxygen is $8.$
Therefore, for $O$ electron configuration will be $1 s^2 2 s^2 2 p^4$.
The distribution of electrons in oxygen atom is given by:
First orbit or $K$ shell = $2\left(2 n^2=2 \times 1^1=2\right)$
Second orbit or $L$ shell $= 6(8 − 2 = 6)$
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