
$(A)$ $E_A^{\text {lnside }}=0$
$(B)$ $Q_A > Q_B$
$(C)$ $\frac{\sigma_A}{\sigma_B}=\frac{R_B}{R_A}$
$(D)$ $E_A^{\text {on sulface }} < E_B^{\text {on uurface }}$

Reason : Charges in a conductor reside only at its surface

(given the value of relative permitivity of material is $50$ )