What is the equivalent capacitance between $A$ and $B$ in the given figure (all are in farad)
Medium
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(d) The given circuit can be simplified as follows
Hence equivalent capacitance between $A$ and $B$
$\frac{1}{{{C_{AB}}}} = \frac{1}{{12}} + \frac{1}{{20/3}} + \frac{1}{{16}}$ $==>$ ${C_{AB}} = \frac{{240}}{{71}}\,F$
Hence equivalent capacitance between $A$ and $B$
$\frac{1}{{{C_{AB}}}} = \frac{1}{{12}} + \frac{1}{{20/3}} + \frac{1}{{16}}$ $==>$ ${C_{AB}} = \frac{{240}}{{71}}\,F$
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