Question
What is the expression for minimum angular momentum of electron in hydrogen atom?

Answer

h/2π
According to Bohr's atomic theory, the orbital angular momentum of an electron is an integral multiplt of h/2π.
\(\therefore L_u=\frac{n h}{2 \pi}\)
Here,
n = Principal quantum number
The minimum value of n is 1.
Thus, the minimum value of the orbital angular momentum of the electron in a hydrogen atom is given by
\(L=\frac{h}{2 \pi}\)

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