MCQ
What is the kinetic energy of an electron in second excited state of $He^+$ ? (Energy of electron in first shell of $H = -13.6\, eV$) :- ............. $\mathrm{eV}$
  • A
    $1.51$
  • $6.04$
  • C
    $13.08$
  • D
    $13.6$

Answer

Correct option: B.
$6.04$
b
$\mathrm{K.E.}=-\mathrm{T.E}=13.6 \frac{\mathrm{z}^{2}}{\mathrm{n}^{2}}=13.6 \frac{(2)^{2}}{(3)^{2}}=6.04\, \mathrm{eV}$

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